How to Avoid Deadlock in Go Goroutines When Producers Are Short-Lived?

Linda Hamilton
Release: 2024-10-25 07:09:02
Original
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How to Avoid Deadlock in Go Goroutines When Producers Are Short-Lived?

Resolving Deadlock in Go Goroutines

In concurrent programming, deadlock occurs when multiple goroutines wait indefinitely for each other to complete operations, effectively halting the program. This article addresses a specific deadlock encountered in Go concurrency, as described in the original question:

<code class="go">package main

import (
    "fmt"
    "time"
)

func producer(ch chan int, d time.Duration, num int) {
    for i := 0; i < num; i++ {
        ch <- i
        time.Sleep(d)
    }
}

func main() {
    ch := make(chan int)
    go producer(ch, 100*time.Millisecond, 2)
    go producer(ch, 200*time.Millisecond, 5)
    for {
        fmt.Println(<-ch)
    }
    close(ch)
}</code>
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This code triggers a deadlock error due to the following factors:

  • The producers, which send values to the channel, are short-lived and eventually stop producing data.
  • The endless for loop in the main function continuously receives values from the channel without a termination condition.
  • The channel is closed after the endless loop, resulting in no further values being available for receiving.

Solution: Coordinated Termination

To avoid deadlock, the producers must be coordinated to signal completion, and the channel must be closed by the last producer. Here's an efficient solution using a sync.WaitGroup for coordination:

<code class="go">func producer(ch chan int, d time.Duration, num int, wg *sync.WaitGroup) {
    defer wg.Done()
    for i := 0; i < num; i++ {
        ch <- i
        time.Sleep(d)
    }
}

func main() {
    wg := &sync.WaitGroup{}
    ch := make(chan int)

    wg.Add(1)
    go producer(ch, 100*time.Millisecond, 2, wg)
    wg.Add(1)
    go producer(ch, 200*time.Millisecond, 5, wg)

    go func() {
        wg.Wait()
        close(ch)
    }()

    for v := range ch {
        fmt.Println(v)
    }
}</code>
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In this solution:

  • We increment the WaitGroup for each producer.
  • Each producer decrements the WaitGroup upon completion through a defer statement.
  • A goroutine waits for the WaitGroup to reach zero (meaning all producers are done) and closes the channel.
  • The main loop uses a for range construct to iterate over the values sent on the channel before it is closed.

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