Understanding JSON unmarshaling can be challenging. This article explores an issue encountered while unmarshaling a map in Go using the following code snippet:
<code class="go">import ( "encoding/json" "fmt" ) type OHLC_RESS struct { Pair map[string][]Candles Last int64 `json:"last"` } type Candles struct { // ... } func (c *Candles) UnmarshalJSON(d []byte) error { // ... } func main() { // ... }</code>
Upon running the code, the Pair map remains empty, despite the Last field being unmarshaled correctly.
Option 1: Adjust Struct Definition
The simplest solution for the provided JSON example is to eliminate the map and align the struct definition with the JSON structure:
<code class="go">type OHLC_RESS struct { Pair []Candles `json:"XXBTZUSD"` Last int64 `json:"last"` }</code>
Option 2: Implement Custom Unmarshaler
If the map keys are dynamic and cannot be hardcoded in the field tags, a custom implementation of the json.Unmarshaler interface is necessary. This can be achieved by implementing the UnmarshalJSON method in the OHLC_RESS struct:
<code class="go">func (r *OHLC_RESS) UnmarshalJSON(d []byte) error { // ... }</code>
The UnmarshalJSON implementation decodes the JSON keys and values separately, treating the "last" element differently from the rest. The remaining elements are unmarshaled into the Pair map.
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