How to Correctly Declare Multiple Pointers to the Same Object in C ?

Clarifying Multiple Object Pointer Declarations

In C , when declaring multiple pointers on a single line, it's essential to grasp the nuances. In the provided example, the question arises regarding the differences between two seemingly similar code snippets.

Example 1:

<code class="cpp">private:
    sf::Sprite* re_sprite_hair, re_sprite_body, re_sprite_eyes;</code>

This declaration intends to create three pointers to sf::Sprite objects. However, it falsely creates one pointer and two objects. The asterisk () immediately following sf::Sprite applies only to the first variable (re_sprite_hair) and not the subsequent ones.

To rectify this, the declaration should be revised as follows:

<code class="cpp">private:
    sf::Sprite* re_sprite_hair, *re_sprite_body, *re_sprite_eyes;</code>

Here, each variable is explicitly assigned an asterisk, creating three distinct pointers.

Example 2:

<code class="cpp">public:
    Entity()
    {
        re_sprite_eyes = new sf::Sprite();
        re_sprite_hair = new sf::Sprite();
        re_sprite_body = new sf::Sprite();
    }

private:
    sf::Sprite* re_sprite_hair;
    sf::Sprite* re_sprite_body;
    sf::Sprite* re_sprite_eyes;</code>

This version declares three pointers correctly according to the intended purpose. The pointers are properly initialized in the constructor using the 'new' operator.

Conclusion:

When declaring multiple pointers on a single line, it's crucial to place the asterisk adjacent to each variable to avoid confusion and ensure accurate memory management.

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