How to Select a Range of Elements with CSS nth-child?

Barbara Streisand
Release: 2024-10-26 05:25:30
Original
133 people have browsed it

How to Select a Range of Elements with CSS nth-child?

Enhancing CSS Selectors for nth Range

The nth-child selector in CSS allows for precise selection of elements based on their position within a parent element. However, it can be challenging to apply this selector for ranges that are not defined by a specific number.

Extending nth-child Range Selection

Consider the following CSS selector:

<code class="css">.myTableRow td:nth-child(?){
  background-color: #FFFFCC;
}</code>
Copy after login

This selector aims to apply a background color to a range of elements within a with the class "myTableRow." However, the question mark (?) placeholder leaves the range undefined.

To apply this selector to columns 2 to 4, you can use the following CSS:

<code class="css">.myTableRow td:nth-child(n+2):nth-child(-n+4){
    background-color: #FFFFCC;
}</code>
Copy after login

Understanding the Enhanced Selector

This selector uses two additional nth-child sub-selectors:

  • :nth-child(n 2): Selects all children starting from the 2nd position onward.
  • :nth-child(-n 4): Selects all children up to the 4th position.

By combining these two sub-selectors, we effectively create a range that includes elements from the 2nd to 4th positions.

Example Usage

Consider the following HTML table:

<code class="html"><table>
  <tr class="myTableRow">
    <td>column 1</td>
    <td>column 2</td>
    <td>column 3</td>
    <td>column 4</td>
    <td>column 5</td>
  </tr>
</table></code>
Copy after login

Applying the enhanced CSS selector to this table will result in a background color being applied to the 2nd, 3rd, and 4th elements within the "myTableRow" . This is because these elements are within the defined range of 2 to 4.

The above is the detailed content of How to Select a Range of Elements with CSS nth-child?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!