Calculating Percentage in MySQL
When working with a MySQL database, you may encounter the need to calculate percentages based on certain values. One such scenario is determining the percentage of members within a group who have taken a survey.
Problem Statement
Consider the following MySQL database table named "a_test" with four columns: "id", "group_name", "employees", and "surveys". The goal is to calculate the percentage of employees who have participated in the survey based on the number of surveys taken.
Provided SQL Statement
The following SQL statement has been attempted to solve this problem:
<code class="sql">SELECT group_name, employees, surveys, COUNT( surveys ) AS test1, ((COUNT( * ) / ( SELECT COUNT( * ) FROM a_test)) * 100 ) AS percentage FROM a_test GROUP BY employees</code>
Revised Solution
To accurately calculate the percentage of employees who have taken the survey, the following revised SQL statement is provided:
<code class="sql">SELECT group_name, employees, surveys, COUNT( surveys ) AS test1, concat(round(( surveys/employees * 100 ),2),'%') AS percentage FROM a_test GROUP BY employees</code>
Explanation
This ensures that the result is displayed as a percentage with the correct number of decimal places.
Sample Data and Output
Using the following sample data in the "a_test" table:
<code class="sql">INSERT INTO a_test (id, group_name, employees, surveys) VALUES (1, 'Awesome Group A', '100', '0'), (2, 'Awesome Group B', '200', '190'), (3, 'Awesome Group C', '300', '290');</code>
The revised SQL statement produces the following output:
group_name | employees | surveys | percentage |
---|---|---|---|
Awesome Group A | 100 | 0 | 0.00% |
Awesome Group B | 200 | 190 | 95.00% |
Awesome Group C | 300 | 290 | 96.67% |
As evident from the output, the percentage of employees who have taken the survey is calculated correctly. Awesome Group B has 95% participation, while Awesome Group C has 96.67% participation.
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