Here are a few question-based titles based on your provided text, focusing on the problem and its solution: Short and Direct: * PHP Warning: Invalid Argument Supplied for foreach(): How to Fix It? *

Barbara Streisand
Release: 2024-10-26 20:00:29
Original
344 people have browsed it

Here are a few question-based titles based on your provided text, focusing on the problem and its solution:

Short and Direct:

* PHP Warning: Invalid Argument Supplied for foreach(): How to Fix It?
* Why Am I Getting the

PHP Warning: Invalid Argument Supplied for foreach()

This PHP warning occurs when you attempt to iterate over something that is not an array. In your code snippet, you face this issue in two instances:

Iteration 1:

<code class="php">foreach($keywordsXML->PopularSearchResult as $item) {
    // ...
}</code>
Copy after login

Here, $keywordsXML->PopularSearchResult is an object, not an array. To fix this, you should convert it to an array using the get_object_vars() function.

Revised Code:

<code class="php">foreach(get_object_vars($keywordsXML->PopularSearchResult) as $item) {
    // ...
}</code>
Copy after login

Iteration 2:

<code class="php">// get user guides
$guidesXML = getEbayGuides($q);
$guides = array();
foreach ($guidesXML->guide as $guideXML) {
    // ...
}</code>
Copy after login

In this instance, $guidesXML->guide is also an object. To iterate over it, convert it to an array as well.

Revised Code:

<code class="php">// get user guides
$guidesXML = getEbayGuides($q);
$guides = array();
foreach(get_object_vars($guidesXML->guide) as $guideXML) {
    // ...
}</code>
Copy after login

Remember to check if your variables are arrays before using foreach to prevent the "Invalid Argument Supplied for foreach()" warning.

The above is the detailed content of Here are a few question-based titles based on your provided text, focusing on the problem and its solution: Short and Direct: * PHP Warning: Invalid Argument Supplied for foreach(): How to Fix It? *. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!