How to efficiently convert CamelCase to snake_case in Python?

CamelCase to snake_case Conversion in Python

The conversion from CamelCase to snake_case is a frequent transformation in Python programming. This question focuses on finding an efficient way to perform this task.

Proposed Solution

The provided code utilizes the re module to achieve this conversion:

import re

name = 'CamelCaseName'
name = re.sub(r'(?print(name) # camel_case_name

This code employs a regular expression to insert underscores before capital letters, and then converts the resulting string to lowercase. The result is the desired snake_case representation.

Alternative Approaches

If performance is a concern, the regex can be compiled beforehand:

pattern = re.compile(r'(?name = pattern.sub('_', name).lower()

For more advanced cases, a double substitution pass can be used:

def camel_to_snake(name):

name = re.sub('(.)([A-Z][a-z]+)', r'_', name)
return re.sub('([a-z0-9])([A-Z])', r'_', name).lower()

Furthermore, the code can be extended to handle multiple underscores:

def to_snake_case(name):

name = re.sub('(.)([A-Z][a-z]+)', r'_', name)
name = re.sub('__([A-Z])', r'_', name)
name = re.sub('([a-z0-9])([A-Z])', r'_', name)
return name.lower()

Snake_case to PascalCase Conversion

Additionally, a reverse conversion from snake_case to PascalCase is provided:

name = 'snake_case_name'
name = ''.join(word.title() for word in name.split('_'))
print(name) # SnakeCaseName

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