Home Backend Development C++ Why doesn\'t C support template covariance, and how can we address the resulting type safety issues when working with polymorphic templates?

Why doesn\'t C support template covariance, and how can we address the resulting type safety issues when working with polymorphic templates?

Oct 28, 2024 am 08:14 AM

Why doesn't C   support template covariance, and how can we address the resulting type safety issues when working with polymorphic templates?

Templates and Polymorphism in C

Consider the following class structure:

<code class="cpp">class Interface {
  // ...
};

class Foo : public Interface {
  // ...
};

template &lt;class T&gt;
class Container {
  // ...
};</code>
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A constructor of some other class Bar is defined as:

<code class="cpp">Bar(const Container&lt;Interface&gt;&amp; bar) {
  // ...
}</code>
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However, when attempting to call the constructor as follows:

<code class="cpp">Container&lt;Foo&gt; container();

Bar *temp = new Bar(container);</code>
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we encounter a "no matching function" error.

Polymorphism in Templates

The concept of polymorphism in templates, or template covariance, would imply that if class B inherits from class A, then T<B> likewise inherits from T<A>. However, this is not the case in C or other languages like Java or C#.

Reason for Lack of Template Covariance

The absence of template covariance is justified by the need to maintain type safety. Consider the following example:

<code class="cpp">// Class hierarchy
class Fruit {...};
class Apple : public Fruit {...};
class Orange : public Fruit {...};

// Template instantiation using std::vector
int main() {
  std::vector&lt;Apple&gt; apple_vec;
  apple_vec.push_back(Apple()); // Valid

  // With covariance, the following would be allowed
  std::vector&lt;Fruit&gt;&amp; fruit_vec = apple_vec;

  // Adding an Orange to the vector
  fruit_vec.push_back(Orange());

  // Incorrect addition of an orange to an apple vector
}</code>
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This demonstrates the potential for unsafe behavior if templates were covariant. Therefore, T<A> and T<B> are considered completely distinct types, regardless of the relationship between A and B.

Resolving the Issue

One approach to resolving the issue in Java and C# is to use bounded wildcards and constraints, respectively:

<code class="java">Bar(Container&lt;? extends Interface) {...}
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<code class="csharp">Bar&lt;T&gt;(Container&lt;T&gt; container) where T : Interface {...}</code>
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In C , the Boost Concept Check library can provide similar functionality. However, using a simple static assert may be a more practical solution for the specific problem encountered:

<code class="cpp">static_assert(std::is_base_of&lt;Interface, Foo&gt;::value, "Container must hold objects of type Interface or its derived classes.");</code>
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