Home > Java > javaTutorial > body text

How to Deserialize Nested Generic Objects in Jackson with Type Erasure?

DDD
Release: 2024-10-28 16:15:43
Original
752 people have browsed it

How to Deserialize Nested Generic Objects in Jackson with Type Erasure?

Jackson and Generic Type Reference

When attempting to use Jackson's JSON library with generic methods, developers may encounter an issue where a nested custom object is returned as a LinkedHashMap instead of its actual class. This problem arises due to Java's type erasure, which removes type information during compilation.

In the provided code, the tester method aims to parse a JSON request into a MyRequest object with a generic type T. However, without specifying the actual class for T, Jackson defaults to treating it as T extends Object and binds JSON objects to maps.

To resolve this, the tester method should have access to the actual class when deserializing the JSON request. This can be achieved by specifying it as a Class argument. The following code demonstrates how to do this:

<code class="java">public MyRequest<T> tester(Class<T> clazz) {
    TypeReference<MyWrapper<T>> typeRef = new TypeReference<MyWrapper<T>>() {};
    MyWrapper<T> requestWrapper = (MyWrapper<T>) JsonConverter.fromJson(jsonRequest, typeRef);
    return requestWrapper.getRequest();
}</code>
Copy after login

Additionally, to ensure that the actual class is used during deserialization, construct a JavaType using the TypeFactory as follows:

<code class="java">JavaType type = mapper.getTypeFactory().constructCollectionType(List.class, clazz);</code>
Copy after login

With this modification, Jackson will deserialize the JSON request into a List containing instances of the specified class, allowing the getMyObject() method to return the object with the appropriate type.

The above is the detailed content of How to Deserialize Nested Generic Objects in Jackson with Type Erasure?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!