How to store multiple user inputs in a vector in C ?

Understanding User Input Storage in Vectors

In C , a vector is a dynamic array that can efficiently store a collection of elements. When it comes to storing user input in a vector, the process involves using the std::cin stream to read input from the console and pushing it into the vector using the std::vector::push_back() method.

Code Structure

Consider the following code snippet:

<code class="cpp">#include <iostream>
#include <vector>

using namespace std;

template <typename T>
void write_vector(const vector<T>& V)
{
   cout << "The numbers in the vector are : ";
   for (int i=0; i < V.size(); i++)
      cout << V[i] << " ";
}

int main()
{
  int input;
  vector<int> V;
  cout << "Enter your numbers to be evaluated: ";
  cin >> input;
  V.push_back(input);
  write_vector(V);
  return 0;
}</code>

Problem Explanation

In this code, the only one number is read from the console and stored in the vector. The write_vector() function then prints the vector, displaying only the first entered number.

Solution

To fix this issue, a loop can be introduced to continuously read inputs from cin until the user enters a non-numeric value, an EOF character, or a specified sentinel value.

<code class="cpp">int main()
{
  int input;
  vector<int> V;

  cout << "Enter your numbers to be evaluated (Enter any non-numeric character to stop): ";
  while (cin >> input)
     V.push_back(input);

  return 0;
}</code>

By using a loop, the code will read multiple inputs and store them in the vector, enabling the write_vector() function to print all the entered numbers.

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