Why Do Lambda Expressions Capture the Final Value of Iterator Variables in C#?

Using Lambda Expressions with Iterators in C#

In C#, lambda expressions provide a concise and convenient way to define anonymous functions. However, a common pitfall when using lambda expressions with iterators is that the captured variable is not the current value of the iterator variable, but rather the final value.

Consider the following code:

<code class="c#">Type[] types = new Type[] { typeof(string), typeof(float), typeof(int) };
List&lt;PrintHelloType&gt; helloMethods = new List&lt;PrintHelloType&gt;();

foreach (var type in types)
{
    var sayHello = new PrintHelloType(greeting =&gt; SayGreetingToType(type, greeting));
    helloMethods.Add(sayHello);
}

foreach (var helloMethod in helloMethods)
{
    Console.WriteLine(helloMethod("Hi"));
}</code>

When you execute this code, you might expect it to print the following output:

Hi String
Hi Single
Hi Int32

However, the actual output is:

Hi Int32
Hi Int32
Hi Int32

This is because the lambda expression captures the loop variable type, not its value at the time the lambda is defined. Therefore, when the lambda is executed, it uses the final value of type, which is Int32.

To fix this issue and obtain the desired output, you can use a local variable to capture the current value of the iterator variable, as shown in the following code:

<code class="c#">foreach (var type in types)
{
    var newType = type;
    var sayHello = new PrintHelloType(greeting =&gt; SayGreetingToType(newType, greeting));
    helloMethods.Add(sayHello);
}</code>

In this case, the lambda expression captures the local variable newType, which is assigned the current value of type. This ensures that the lambda expression uses the correct value of type when it is executed.

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