Why Does My C Code Throw \'ISO C forbids comparison between pointer and integer\'?

Compiler Error: Pointer and Integer Comparison Prohibition in C

The compiler issue "ISO C forbids comparison between pointer and integer" arises during compilation, highlighting a code error relating to improper comparison between a pointer and an integer. To delve into the resolution, let's examine the provided code:

In the given code, the error occurs within the if statement where answer is being tested against "y":

<code class="cpp">if (answer == "y") ...</code>

Here, answer is a character variable, whereas "y" is a C-style string literal. Attempting to compare a character variable to a pointer to a character (as "y" translates to a pointer) triggers the compiler error.

You have two potential solutions to address this issue:

1. Use String Variable:

The preferred solution is to employ a string variable for answer instead of a character variable:

<code class="cpp">string answer;</code>

This aligns with best practices and avoids the pointer-integer comparison error.

2. Use Character Constant:

Alternatively, you can utilize a character constant with single quotes, which represents a character rather than a string:

<code class="cpp">if (answer == 'y') ...</code>

Both solutions effectively resolve the pointer-integer comparison prohibition, ensuring correct code execution.

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