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Why Does \'SELECT ... WHERE ... IN ...\' Fail in MySQLdb with Parameterized Queries?

Barbara Streisand
Release: 2024-10-29 21:46:02
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Why Does

Executing "SELECT ... WHERE ... IN ..." using MySQLdb

Executing a SQL query with the IN clause using MySQLdb can be challenging, particularly when SQL parameters are employed. While a similar query may function correctly from the mysql command-line, its execution in Python may encounter difficulties.

Case Study

Consider the following SQL query:

SELECT fooid FROM foo WHERE bar IN ('A', 'C')
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When attempting to execute this query from within Python using the mysql command, the following SQL is generated:

<code class="python">sql = 'SELECT fooid FROM foo WHERE bar IN %s'
args = [['A', 'C']]</code>
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However, upon execution, this query returns no rows, despite expecting two. Interestingly, by switching the roles of bar and fooid in the Python query, the expected rows are successfully retrieved:

<code class="python">sql = 'SELECT bar FROM foo WHERE fooid IN %s'
args = [[1, 3]]</code>
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Root Cause

The discrepancy in behavior stems from the way MySQLdb converts the parameterized argument ['A', 'C'] to ("'''A''"', "'''''C''"'") while executing the query. The excessive quotation marks render the IN clause ineffective.

Solution

Since MySQLdb lacks a built-in method to bind a list to an IN clause, the query parameters must be manually constructed as follows:

<code class="python"># Python 3
args = ['A', 'C']
sql = 'SELECT fooid FROM foo WHERE bar IN (%s)' 
in_p = ', '.join(list(map(lambda x: '%s', args)))
sql = sql % in_p

# Python 2
args = ['A', 'C']
sql = 'SELECT fooid FROM foo WHERE bar IN (%s)' 
in_p = ', '.join(map(lambda x: '%s', args))
sql = sql % in_p</code>
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By manually constructing the IN clause with the correct number of placeholders, the query can be executed successfully, returning the expected rows.

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