How Can I Read Integer Values in Go Without a For Loop?

Efficiently Reading Integer Values in Golang

To read a set of integer values from standard input and store them in a slice without using a conventional for loop, an optimized approach can be employed.

Solution Using Recursive Function

This approach utilizes a recursive function, ReadN, which takes an integer slice, a starting index, and the number of integers to read. Through successive recursive calls, it efficiently assigns integers to the slice.

Sample Code:

<code class="go">package main

import "fmt"

func main() {
    fmt.Println(`Enter the number of integers`)
    var n int
    if m, err := Scan(&n); m != 1 {
        panic(err)
    }
    fmt.Println(`Enter the integers`)
    all := make([]int, n)
    ReadN(all, 0, n)
    fmt.Println(all)
}

func ReadN(all []int, i, n int) {
    if n == 0 {
        return
    }
    if m, err := Scan(&all[i]); m != 1 {
        panic(err)
    }
    ReadN(all, i+1, n-1)
}

func Scan(a *int) (int, error) {
    return fmt.Scan(a)
}</code>

Faster Input Scanning

For even faster input scanning, replace the custom Scan function with a more efficient alternative:

<code class="go">func Scan(a *int) (int, error) {
    return fmt.Scanf("%d\n", a)
}</code>

Sample Input and Output:

Enter the number of integers
3
Enter the integers
10 20 30
[10 20 30]

This optimized solution provides an efficient way to read integers from standard input, without the overhead of a for loop.

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