In Go, it's often necessary to reference a struct as a pointer, particularly when working with object-oriented patterns. However, when embedding a struct within another struct that is used as a pointer, there's a choice to be made: embed the struct itself or a pointer to it. This decision has subtle implications that can affect code behavior.
Consider the following code:
<code class="go">type B struct { X int } type A struct { B }</code>
Here, the B struct is embedded directly within the A struct. The zero value of A includes an embedded object of type B, which also has its zero value. As a result, we can safely call the Print method of the embedded B object:
<code class="go">var a A a.Print() // prints 0</code>
In contrast, consider the following code:
<code class="go">type B struct { X int } type A struct { *B }</code>
Here, the B struct is embedded as a pointer within the A struct. The zero value of A has a nil pointer value for the embedded *B. Attempting to call the Print method on the embedded *B object will result in a panic:
<code class="go">var a A a.Print() // panics</code>
When creating new objects of these types, the behavior differs:
The choice between embedding the struct directly or using a pointer depends on the intended use case. Embedding the struct provides the convenience of accessing the embedded fields directly, while embedding a pointer allows for modifications to the embedded struct to affect multiple copies. Understanding these implications ensures proper usage and avoids potential pitfalls in your code.
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