Problem:
How can we retrieve specific date and time components, such as year, month, day, hours, minutes, seconds, and milliseconds, from an std::chrono::time_point object?
Solution:
To extract this information, we must utilize the system_clock::time_point as it's the only system-supplied clock that has a connection to the civil calendar.
<code class="cpp">system_clock::time_point now = system_clock::now();</code>
Converting to a Time Stamp:
Next, convert the time_point to a time_t:
<code class="cpp">time_t tt = system_clock::to_time_t(now);</code>
Extracting Components:
Using the C library, convert the time_t to a tm, specifying whether you want conversion in UTC or the local time zone:
<code class="cpp">tm utc_tm = *gmtime(&tt); tm local_tm = *localtime(&tt);</code>
Now, you can print the components of the tm:
<code class="cpp">std::cout << local_tm.tm_year + 1900 << '\n'; std::cout << local_tm.tm_mon + 1 << '\n'; std::cout << local_tm.tm_mday << '\n';
Extended Extraction:
While system_clock is typically based on Unix time, its precision is often greater than seconds. To access the high-resolution components, use the following code:
<code class="cpp">using namespace std; using namespace std::chrono; int main() { typedef duration<int, ratio_multiply<hours::period, ratio<24> >>::type days; system_clock::time_point now = system_clock::now(); system_clock::duration tp = now.time_since_epoch(); days d = duration_cast<days>(tp); tp -= d; hours h = duration_cast<hours>(tp); tp -= h; minutes m = duration_cast<minutes>(tp); tp -= m; seconds s = duration_cast<seconds>(tp); tp -= s; cout << d.count() << "d " << h.count() << ':' << m.count() << ':' << s.count(); cout << " " << tp.count() << "[" << system_clock::duration::period::num << '/' << system_clock::duration::period::den << "]\n"; }
By converting the time_point to days, hours, minutes, seconds, and extracting the fraction of a second, this code outputs:
15806d 20:31:14 598155[1/1000000]
Library Solutions:
The header-only date library simplifies this process, allowing the extraction with the following code:
<code class="cpp">#include "date.h" int main() { auto tp = std::chrono::system_clock::now(); auto dp = date::floor<date::days>(tp); auto ymd = date::year_month_day{dp}; auto time = date::make_time(std::chrono::duration_cast<std::chrono::milliseconds>(tp - dp)); std::cout << "year = " << ymd.year() << '\n'; std::cout << "month = " << ymd.month() << '\n'; std::cout << "day = " << ymd.day() << '\n'; std::cout << "hour = " << time.hours().count() << "h\n"; std::cout << "minute = " << time.minutes().count() << "min\n"; std::cout << "second = " << time.seconds().count() << "s\n"; std::cout << "millisecond = " << time.subseconds().count() << "ms\n"; }
C 20 Integration:
In C 20, a proposed syntax is included for extracting these fields using system_clock::time_point:
<code class="cpp">#include <chrono> int main() { using namespace std::chrono; auto tp = system_clock::now(); auto dp = floor<days>(tp); year_month_day ymd{dp}; hh_mm_ss time{floor<milliseconds>(tp - dp)}; auto y = ymd.year(); auto m = ymd.month(); auto d = ymd.day(); auto h = time.hours(); auto M = time.minutes(); auto s = time.seconds(); auto ms = time.subseconds(); }</code>
Additionally, you can specify a preferred time zone for the extraction.
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