Why Am I Getting \'The Specified Child Already Has a Parent\' Error in Android?

Error: The Specified Child Already Has a Parent (Android)

Problem:

Frequently switching between two layouts results in the following error:

FATAL EXCEPTION: main
java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.

Code Snippet:

<code class="java">tv = new TextView(getApplicationContext()); // initialized elsewhere
et = new EditText(getApplicationContext()); // initialized elsewhere

private void ConsoleWindow() {
    runOnUiThread(new Runnable() {
        @Override
        public void run() {
            // MY LAYOUT:
            setContentView(R.layout.activity_console);
            // LINEAR LAYOUT
            LinearLayout layout = new LinearLayout(getApplicationContext());
            layout.setOrientation(LinearLayout.VERTICAL);
            setContentView(layout);

            // TEXTVIEW
            layout.addView(tv); // ERROR IN THIS LINE DURING 2ND RUN
            // EDITTEXT
            et.setHint("Enter Command");
            layout.addView(et);
        }
    });
}</code>

Solution:

The error message suggests removing the child (TextView) from its current parent before adding it to the new layout.

Add the following code before layout.addView(tv);:

<code class="java">if (tv.getParent() != null) {
    ((ViewGroup) tv.getParent()).removeView(tv); // Fix
}</code>

This ensures that the TextView is properly removed from any existing parent before being added to the new layout, preventing the specified parent conflict.

The above is the detailed content of Why Am I Getting \'The Specified Child Already Has a Parent\' Error in Android?. For more information, please follow other related articles on the PHP Chinese website!