Home > Java > javaTutorial > body text

How Do You Efficiently Convert a Char to a String in Java?

Linda Hamilton
Release: 2024-10-31 08:36:30
Original
644 people have browsed it

 How Do You Efficiently Convert a Char to a String in Java?

String Conversion Dilemma: Converting a Char to a String

Problem:

In the realm of programming, you encounter scenarios where a char, a single character, needs to transform into a String. This conversion process raises the question: how do we seamlessly achieve this transformation?

Solution:

To morph a char into a String, you can rely on the Character.toString(char) method. This technique is a straightforward approach that returns the character enclosed in a String. Alternatively, you can employ the String.valueOf(char) method, which essentially performs the same task.

Concatenation Shortcut:

Some programmers utilize string concatenation as a shortcut for char to String conversion. This method involves appending the char to an empty String:

String s = "" + 's';
Copy after login

However, this seemingly convenient method actually compiles down to a less efficient process:

String s = new StringBuilder().append("").append('s').toString();
Copy after login

This approach incurs performance overhead because it allocates a char[] that may be larger than necessary and then makes a defensive copy of the array when creating the String.

String.valueOf(char): A More Efficient Option:

The String.valueOf(char) method stands out as a more efficient solution. It bypasses the char[] allocation by wrapping the char in a single-element array and passing it directly to a package-private String constructor. This maneuver evades the potentially unnecessary array copy, resulting in improved performance.

The above is the detailed content of How Do You Efficiently Convert a Char to a String in Java?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!