In working with datasets, it is often necessary to compute differences or changes between values over time or across different categories. In Pandas, you can efficiently perform these calculations by utilizing the groupby() and diff() functions.
In the given scenario, you have a DataFrame with data on various websites and their scores in different countries. Your goal is to determine the 1/3/5-day score difference for each site country combination.
To begin, sort your DataFrame by the site, country, and date columns. Sorting ensures that similar data points are grouped together, making it easier to calculate differences.
<code class="python">df = df.sort_values(by=['site', 'country', 'date'])</code>
Next, use the groupby() function to group the data by site and country.
<code class="python">grouped = df.groupby(['site', 'country'])</code>
With the data grouped, you can now calculate the score differences using the diff() function. This function computes the difference between consecutive rows in a group.
<code class="python">df['diff'] = grouped['score'].diff().fillna(0)</code>
The diff() function fills missing values with 0 by default, ensuring a consistent and complete dataset.
The resulting DataFrame will contain the original data along with the calculated score differences:
date site country score diff 8 2018-01-01 fb es 100 0.0 9 2018-01-02 fb gb 100 0.0 5 2018-01-01 fb us 50 0.0 6 2018-01-02 fb us 55 5.0 7 2018-01-03 fb us 100 45.0 1 2018-01-01 google ch 50 0.0 4 2018-01-02 google ch 10 -40.0 0 2018-01-01 google us 100 0.0 2 2018-01-02 google us 70 -30.0 3 2018-01-03 google us 60 -10.0
This DataFrame provides the desired 1/3/5-day score difference for each site/country combination.
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