Is There a Performance Difference Between \'make\' and \'{}\' for Initializing Maps in Go?

In Go, Unveiling the Performance Gap Between Maps Initialized Using "make" vs "{}"

In Go, developers have the flexibility to initialize maps in two ways: "make" and "{} syntax. This naturally raises the question of whether there are any performance differences between these approaches.

To compare the performance, a benchmark test can be created to measure the time taken to initialize a map using both methods. The provided benchmark test, as shown below, illustrates this:

<code class="go">package bench

import "testing"

var result map[string]int

func BenchmarkMakeLiteral(b *testing.B) {
    var m map[string]int
    for n := 0; n < b.N; n++ {
        m = InitMapLiteral()
    }
    result = m
}

func BenchmarkMakeMake(b *testing.B) {
    var m map[string]int
    for n := 0; n < b.N; n++ {
        m = InitMapMake()
    }
    result = m
}

func InitMapLiteral() map[string]int {
    return map[string]int{}
}

func InitMapMake() map[string]int {
    return make(map[string]int)
}</code>

Running this benchmark on multiple occasions yields results that suggest they are practically equivalent in terms of performance:

$ go test -bench=.
testing: warning: no tests to run
PASS
BenchmarkMakeLiteral-8  10000000               160 ns/op
BenchmarkMakeMake-8     10000000               171 ns/op
ok      github.com/johnweldon/bench     3.664s

$ go test -bench=.
testing: warning: no tests to run
PASS
BenchmarkMakeLiteral-8  10000000               182 ns/op
BenchmarkMakeMake-8     10000000               173 ns/op
ok      github.com/johnweldon/bench     3.945s

$ go test -bench=.
testing: warning: no tests to run
PASS
BenchmarkMakeLiteral-8  10000000               170 ns/op
BenchmarkMakeMake-8     10000000               170 ns/op
ok      github.com/johnweldon/bench     3.751s

This indicates that, on average, the performance difference between initializing maps using "make" vs "{} syntax is negligible and can be considered essentially equivalent.

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