Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays.
The overall run time complexity should be O(log (m n))
Example 1: Input: nums1 = [1,3], nums2 = [2] Output: 2.00000 Explanation: merged array = [1,2,3] and median is 2. Example 2: Input: nums1 = [1,2], nums2 = [3,4] Output: 2.50000 Explanation: merged array = [1,2,3,4] and median is (2 + 3) / 2 = 2.5.
Constraints:
nums1.length == m
nums2.length == n
0 <= m <= 1000
0 <= n <= 1000
1 <= m n <= 2000
-106 <= nums1[i], nums2[i] <= 106
var findMedianSortedArrays = function(nums1, nums2) { const toltalLength = nums1.length + nums2.length;let x = 0; let y = 0; const mergedArr = [] for(let i=0; i< toltalLength;i++){ if(x> nums1.length -1){ nums2.splice(0, y) mergedArr.push(...nums2) break; } if(y> nums2.length -1){ nums1.splice(0, x) mergedArr.push(...nums1) break; } if(nums1[x] > nums2[y]){ mergedArr.push(nums2[y]); y++; continue; }else{ mergedArr.push(nums1[x]); x++; continue; } } if(toltalLength % 2 === 0){ return (mergedArr[toltalLength/2] + mergedArr[toltalLength/2 -1]) /2 }else{ return mergedArr[(toltalLength-1)/2] } };The above is the detailed content of Median of Two Sorted Arrays. For more information, please follow other related articles on the PHP Chinese website!