Why Does Java Throw \'The Literal xyz of Type int Is Out of Range\' When Assigning to a Long Variable?

Fixing "The Literal xyz of Type int Is Out of Range"

When working with data types in Java, it's essential to understand their value ranges. However, you may encounter an error stating "The literal xyz of type int is out of range," even when assigning a value to a long variable.

To resolve this, the key is to explicitly specify the type of the value. In Java, integer values up to 2^31-1 can be represented by int, while larger values require long. However, Java implicitly interprets numeric literals as int unless explicitly specified otherwise.

In your case, the code assigns a value greater than 2^63-1 to a long variable named testLong. Since the literal 9223372036854775807 exceeds the range of int, the compiler interprets it as such, leading to the error.

To fix this, simply append a capital L to the end of the numeric literal to indicate that it represents a long value:

<code class="java">long testLong = 9223372036854775807L;</code>

By explicitly specifying the type of the literal, you ensure that the compiler correctly assigns it to the appropriate data type. This practice is particularly important when working with literals that are close to the maximum or minimum values of a data type to avoid potential errors.

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