How to Stream Large MP4 Videos Efficiently with GoLang?

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Release: 2024-11-01 08:16:02
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How to Stream Large MP4 Videos Efficiently with GoLang?

Serving Video Content with Golang

Serving video content using GoLang can be a straightforward task. However, when attempting to serve MP4 videos in a webserver, you may encounter issues.

One such issue involves serving large video files. By default, browsers such as Chrome rely on a buffer to play videos. If the video size exceeds the buffer capacity, the video may fail to play or display incompletely.

To address this issue, you need to ensure that your server supports partial content serving. This is typically done using the http.ServeFile() method, which handles Range requests from browsers. Range requests allow browsers to request specific portions of a file, enabling them to progressively download and play videos.

Serving MP4 Videos

To serve MP4 videos in your webserver using GoLang, you can use the http.ServeFile() method in your HTTP handler:

func (vh *viewHandler) ServeHTTP(w http.ResponseWriter, r *http.Request) {
    path := r.URL.Path[1:]
    log.Println(path)

    if strings.HasSuffix(path, ".mp4") {
        http.ServeFile(w, r, string(path))
        return
    }

    // Handle other file types as before...
}
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Conclusion

By using the http.ServeFile() method, you can effectively serve MP4 videos in your webserver. This ensures that the video content is properly streamed, allowing browsers to play large videos without any issues.

The above is the detailed content of How to Stream Large MP4 Videos Efficiently with GoLang?. For more information, please follow other related articles on the PHP Chinese website!

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