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Why does comparing `float` and `double` values sometimes return `false` even when they appear identical?

Barbara Streisand
Release: 2024-11-01 18:19:30
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Why does comparing `float` and `double` values sometimes return `false` even when they appear identical?

Unexpected Results When Comparing Double and Float Data Types

When comparing double precision floating-point numbers (double) to single precision floating-point numbers (float), you may encounter unexpected results. Specifically, the equality check (f == d) between a float variable f and a double variable d may return false even though both values appear to be identical.

This behavior stems from two fundamental factors associated with floating-point numbers: precision and rounding.

Precision and Rounding Errors

  • Precision: Floating-point numbers store a limited number of digits, which determines the accuracy of the values they can represent. Certain numbers, such as 1/3 in decimal, have an infinite decimal representation and cannot be exactly stored without losing precision.
  • Rounding: When a floating-point value is converted to binary, it may not be able to represent certain decimal values exactly. For instance, 0.1 in decimal is represented in binary as an infinite sequence of digits. As a result, floating-point numbers undergo rounding to fit within their有限s.

Implications for Equality Checks

The precision and rounding inherent in floating-point numbers can lead to rounding errors, especially when comparing values very close to each other. These errors accumulate, causing the equality comparison to fail. This makes direct equality checking for floating-point numbers unreliable and prone to false negatives.

Solution: Comparing with an Epsilon

Instead of using equality checks, a more reliable method for comparing floating-point numbers is to take the absolute difference between them and check if it is below a small value known as an epsilon (ε). This allows you to account for rounding errors and determine if the difference is insignificant for your application.

if (abs(x - y) < epsilon)
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