Home > Backend Development > C++ > body text

How can std::string\'s rfind be used to check for a prefix and convert a substring to an integer?

Linda Hamilton
Release: 2024-11-01 19:41:30
Original
575 people have browsed it

How can std::string's rfind be used to check for a prefix and convert a substring to an integer?

Using std::string's rfind Overloads to Check for Prefix and Convert Substring to Int

To determine if a C std::string begins with a specific string and convert a substring to an integer, you can leverage the overloaded rfind function.

Checking for String Prefix

Use the rfind overload that accepts a search position parameter (pos). Setting this parameter to zero restricts the search to the beginning of the string:

<code class="cpp">std::string s = "tititoto";
if (s.rfind("titi", 0) == 0) {
  // The string s starts with the "titi" prefix.
}</code>
Copy after login

Converting Substring to Int

To extract a substring after a known prefix and convert it to an integer, you can use a combination of rfind and substr:

<code class="cpp">std::string arg = "--foo=98";
size_t pos = arg.rfind("--foo=");
if (pos != std::string::npos) {
  std::string fooValue = arg.substr(pos + len("--foo="));
  int value = std::stoi(fooValue);
}</code>
Copy after login

In this example, if arg is "--foo=98", the variable value will be assigned the integer value 98.

STL Advantage

This approach avoids the need for external libraries like Boost. It utilizes the standard string manipulations provided by the STL, which are straightforward to implement and efficient.

C 20 Simplification

In C 20 and later, the std::string and std::string_view classes introduce the starts_with method, which makes checking for a prefix even simpler:

<code class="cpp">std::string s = "tititoto";
if (s.starts_with("titi")) {
  // The string s starts with the "titi" prefix.
}</code>
Copy after login

The above is the detailed content of How can std::string\'s rfind be used to check for a prefix and convert a substring to an integer?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!