Why Does \'Fatal error: Call to undefined method mysqli_stmt::fetch_array()\' Occur When Using Prepared Statements?

Fixing "Fatal error: Call to undefined method mysqli_stmt::fetch_array() [duplicate]"

In your code, you're attempting to use mysqli_stmt::fetch_array() when using prepared statements. This function is not available for prepared statements.

Solution:

Instead, you should use mysqli_stmt::fetch() to retrieve a single row of data, or mysqli_result::fetch_all() to retrieve multiple rows.

Revised code:

<code class="php">$search = "player";

$sql = $db->prepare('select job from jobs where job like ?');
$sql->bind_param('s', $search);
$sql->execute();
$result = $sql->get_result(); // Get the result object

$data = array();

while ($row = $result->fetch_assoc()) {
    $data[] = array(
        'label' => $row['job']
    );
    echo json_encode($data);
}

$sql->close();
$db->close();</code>

By using mysqli_stmt::fetch_array() or mysqli_result::fetch_assoc(), you can retrieve the data from the database successfully without encountering the error.

The above is the detailed content of Why Does \'Fatal error: Call to undefined method mysqli_stmt::fetch_array()\' Occur When Using Prepared Statements?. For more information, please follow other related articles on the PHP Chinese website!