Why Does \'(0 < 5 < 3)\' Evaluate to True in JavaScript?

Unveiling the Truth Behind "(0 < 5 < 3)"

In the realm of programming, the order of precedence governs how expressions are evaluated. In the case of "(0 < 5 < 3)", the evaluation follows a specific order, leading to an unexpected result of "true".

Delving deeper into the mechanics:

• Operator Precedence: Comparisons ("<") take precedence over logical operators ("&&").
• Associativity: Comparisons associate from left to right.

Therefore, "(0 < 5 < 3)" is interpreted as "((0 < 5) < 3)".

Evaluating the Nested Expressions:

1. (0 < 5): True
2. (true < 3): True

Since true is interpreted as 1 in JavaScript, (true < 3) evaluates to (1 < 3), resulting in "true". Hence, the entire expression "(0 < 5 < 3)" returns "true".

An Interesting Quirk:

This peculiar behavior can be exploited to achieve certain outcomes. For instance, it can be helpful in executing logical operations conditionally.

Example:

<code class="javascript">let result = (condition) ? (0 < 5 < 3) : (5 < 3 < 0);</code>

If condition is true, the result will be "true" because the expression "(0 < 5 < 3)" evaluates to "true". Otherwise, the result will be "false" because the expression "(5 < 3 < 0)" evaluates to "false".

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