Filtering Array of Objects Using Another Array of Objects
The task at hand is to filter an array of objects (myArray) based on a second array of objects (myFilter) to return only those objects in myArray whose userid and projectid properties match those in myFilter.
Solution
To achieve this, we utilize a combination of filter and some methods. The filter method iterates over each element in myArray and returns a new array containing only those elements that pass a given condition. In this case, the condition is satisfied if the element's userid and projectid match any of the userid and projectid pairs in myFilter.
The some method is used within the filter condition to determine whether any of the elements in myFilter meet the specified criteria. The condition checks whether the current myFilter element's userid and projectid properties are equal to those of the current myArray element. If a match is found, the some method returns true, indicating that the condition is met and the element should be included in the filtered array.
Code Example
<code class="js">const myArray = [ { userid: "100", projectid: "10", rowid: "0" }, { userid: "101", projectid: "11", rowid: "1"}, { userid: "102", projectid: "12", rowid: "2" }, { userid: "103", projectid: "13", rowid: "3" }, { userid: "101", projectid: "10", rowid: "4" } ]; const myFilter = [ { userid: "101", projectid: "11" }, { userid: "102", projectid: "12" }, { userid: "103", projectid: "11"} ]; const myArrayFiltered = myArray.filter((el) => { return myFilter.some((f) => { return f.userid === el.userid && f.projectid === el.projectid; }); }); console.log(myArrayFiltered);</code>
Output
[ { userid: "101", projectid: "11", rowid: "1" }, { userid: "102", projectid: "12", rowid: "2" } ]
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