Out-of-Class Definition of Template Member Functions
In C , when defining template class member functions outside of the class definition, it is necessary to specify both the class template parameters and the function member template parameters. This allows the function to access the context of both the class and the function template.
The syntax for defining a template member function outside of the class definition is as follows:
template<class T> template <class U> void Foo<T>::bar() { // Function body }
In this example, Foo is the template class, T is the class template parameter, U is the function member template parameter, and bar is the function member name.
To illustrate the usage, consider the following code snippet:
<code class="cpp">template <class T> class Foo { public: template <class U> void bar(); }; template<> template <class U> void Foo<int>::bar() { // Implementation that uses both T and U }</code>
In this code, the bar function member is defined outside of the Foo class definition, but it still has access to both the class template parameter T and the function member template parameter U.
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