In programming, maintaining unique elements in a list is essential for ensuring data integrity and preventing redundancy. However, implementing efficient duplicate removal can sometimes be challenging.
The code provided in the question attempts to remove duplicates by checking if an element already exists in the list using the contains method. However, this approach has a significant time complexity and is not optimal for large lists. To resolve this issue, we present several improved solutions.
One effective method involves using a LinkedHashSet. It maintains the order of elements while automatically eliminating duplicates. Here's how to implement it:
<code class="java">List<Customer> dedupeCustomers = new ArrayList<>(new LinkedHashSet<>(customers));</code>
Alternatively, if you wish to modify the original list:
<code class="java">Set<Customer> dedupeCustomers = new LinkedHashSet<>(customers); customers.clear(); customers.addAll(dedupeCustomers);</code>
This approach ensures that the list contains only unique elements, preserving the original order if desired. By utilizing these methods, you can efficiently remove duplicates while maintaining data integrity and efficiency.
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