Home > Backend Development > C++ > How to Print Addresses with Char Pointers Using `cout`?

How to Print Addresses with Char Pointers Using `cout`?

DDD
Release: 2024-11-03 21:10:03
Original
919 people have browsed it

How to Print Addresses with Char Pointers Using `cout`?

Cout Interpretation of Char Pointers

Unlike printf(), which offers specific conversion specifiers (%u or %s) to determine whether to print an address or the entire string pointed to by a char pointer, cout requires an explicit approach for this distinction.

Example Problem:

Consider the following code snippet:

<code class="cpp">int main() {
  char ch = 'a';
  char *cptr = &ch;
  cout << cptr << endl;
  return 0;
}
Copy after login

In this example, with the default GNU compiler, cout interprets the char pointer as a C-style string and attempts to print the character pointed to by cptr. However, if the intention is to print the address of ch instead, a different approach is necessary.

Solution:

To print the address of ch using cptr with cout, explicit type casting is required. This is achieved by utilizing the static_cast<> operator, as demonstrated below:

<code class="cpp">cout << static_cast<void *>(cptr) << endl;</code>
Copy after login

By explicitly casting cptr to void *, the overload resolution selects the appropriate ostream& operator that takes a void pointer as an argument. This correctly prints the address of ch.

The above is the detailed content of How to Print Addresses with Char Pointers Using `cout`?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template