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How to Compare JSON Objects in Java Without Child Order Considerations?

Patricia Arquette
Release: 2024-11-05 03:23:02
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How to Compare JSON Objects in Java Without Child Order Considerations?

Comparing JSON Objects Without Child Order Considerations in Java

Unit testing JSON responses from web services often requires comparing JSON objects. However, standard libraries like org.json perform reference comparisons, which fail if the child objects are in different orders.

Solution: JSONAssert Library

Skyscreamer's JSONAssert library offers a robust solution for comparing JSON objects. Its non-strict mode provides flexibility by:

  • Allowing object extensibility: Expected value {id:1} will match actual value {id:1,moredata:'x'}
  • Ignoring loose array ordering: ['dog','cat'] will equal ['cat','dog']

Example Usage:

<code class="java">@Test
public void testGetFriends() {
    JSONObject data = getRESTData("/friends/367.json");
    String expected = "{friends:[{id:123,name:\"Corby Page\"}"
        + ",{id:456,name:\"Solomon Duskis\"}]}";
    JSONAssert.assertEquals(expected, data, false);
}</code>
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JSONAssert's clear failure messages facilitate efficient debugging, especially for large JSON objects.

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