Table of Contents
Invalid Datetime Format in JSON Unmarshalling
Background
Problem
Solution
Usage
Notes
Home Backend Development Golang How to Unmarshal JSON with Incorrect Timezone Offset in Go?

How to Unmarshal JSON with Incorrect Timezone Offset in Go?

Nov 05, 2024 am 08:25 AM

How to Unmarshal JSON with Incorrect Timezone Offset in Go?

Invalid Datetime Format in JSON Unmarshalling

Background

Go's JSON unmarshaling has issues with datetimes formatted according to ISO8601/RFC3339 that have timezone offsets in the format 0200 instead of 02:00.

Problem

Incorrect JSON Format:

2016-08-08T21:35:14.052975+0200
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Expected Correct Format:

2016-08-08T21:35:14.052975+02:00
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Possible Cause:

The JSON was generated using C's strftime function with a format string that does not include the colon in the timezone offset.

Solution

To resolve this issue and enable the correct unmarshalling of both formats, a custom time field type can be defined:

<code class="go">type MyTime struct {
    time.Time
}

func (self *MyTime) UnmarshalJSON(b []byte) (err error) {
    s := string(b)

    // Remove double quotes from JSON value
    s = s[1:len(s)-1]

    t, err := time.Parse(time.RFC3339Nano, s)
    if err != nil {
        t, err = time.Parse("2006-01-02T15:04:05.999999999Z0700", s)
    }
    self.Time = t
    return
}</code>
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In this custom type, the UnmarshalJSON method attempts to parse the string according to both RFC3339Nano (with a colon in the timezone offset) and a modified version of RFC3339Nano without the colon.

Usage

To use the custom time field type:

<code class="go">type Test struct {
    Time MyTime `json:"time"`
}</code>
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This struct can then be unmarshalled from either JSON format with the incorrect or correct timezone offset.

Notes

  • By default, the RFC3339Nano format in time.Parse uses "Z" for the timezone offset, while in the modified format, "Z0700" is used.
  • The year "2006" in the time format is a reference to the first year of Go's release.

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