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Why does my PHP code return 'December' instead of 'August' when converting a month number to its name?

Patricia Arquette
Release: 2024-11-06 08:44:02
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Why does my PHP code return

Convert Number to Month Name in PHP

Your PHP code is attempting to convert a month number (8) to its corresponding month name ("August") using the date() function. Unfortunately, the code is returning "December" instead of "August". This is because the $monthNum has been padded with a leading zero ("08") before being passed to the strtotime() function.

Recommended Solution Using DateTime Objects

For accurate and up-to-date date/time manipulation, it is highly recommended to use DateTime objects. Here's an improved version of your code using the DateTime class:

<code class="php">$monthNum  = 8;
$dateObj   = DateTime::createFromFormat('!m', $monthNum);
$monthName = $dateObj->format('F'); // August</code>
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Alternative Solution for Older PHP Versions

If you cannot use DateTime objects, you can create a timestamp using the mktime() function and pass it to the date() function:

<code class="php">$monthNum  = 8;
$monthName = date('F', mktime(0, 0, 0, $monthNum, 10)); // August</code>
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Here, mktime(0, 0, 0, $monthNum, 10) creates a timestamp representing the 10th day of the given month. The 'F' format specifier for date() returns the full month name.

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