Table of Contents
Why Using if(isset($_POST['submit'])) Does Not Display Echoes and Table
Understanding the if(isset()) Function
Missing Name Attribute in Submit Button
How to Fix the Issue
Home Database Mysql Tutorial Why Doesn't My PHP Code Display Echoes and a Table When Using `if(isset($_POST['submit']))`?

Why Doesn't My PHP Code Display Echoes and a Table When Using `if(isset($_POST['submit']))`?

Nov 06, 2024 pm 04:00 PM

Why Doesn't My PHP Code Display Echoes and a Table When Using `if(isset($_POST['submit']))`?

Why Using if(isset($_POST['submit'])) Does Not Display Echoes and Table

In PHP scripting, if(isset($_POST['submit'])) is commonly used to conditionally display content based on whether a form has been submitted. However, this technique is not working in your code because the submit button lacks a proper name attribute.

Understanding the if(isset()) Function

The if(isset()) function checks if a specific variable is set, meaning it has been declared and initialized. In your case, if(isset($_POST['submit'])) checks if the variable $_POST['submit'] exists.

Missing Name Attribute in Submit Button

The problem arises because your submit button does not have a name attribute, as shown here:

<p><input type="submit" value="Submit" /></p>
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Without a name attribute, the submitted form data will not include a $_POST['submit'] variable, making the if(isset($_POST['submit'])) condition always false.

How to Fix the Issue

To fix this, simply add a name attribute to your submit button with a unique value, like so:

<p><input type="submit" value="Submit" name="submit" /></p>
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This will create the necessary $_POST['submit'] variable when the form is submitted.

With this fix, your code will display the echoes and table only when the "Submit" button is clicked, as now if(isset($_POST['submit'])) will evaluate to true when the form is submitted.

...
<p><input type="submit" value="Submit" name="submit" /></p>

if(isset($_POST['submit'])){
    // Display echoes and table
}
....
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