Home > Web Front-end > JS Tutorial > Why Does My Firebase Reference Become Undefined Outside the `once()` Function?

Why Does My Firebase Reference Become Undefined Outside the `once()` Function?

Susan Sarandon
Release: 2024-11-07 02:54:03
Original
548 people have browsed it

Why Does My Firebase Reference Become Undefined Outside the `once()` Function?

Why Does Firebase Lose Reference outside the once() Function?

Firebase utilizes asynchronous processing, which means retrieving data from the database is not executed sequentially. As a result, attempting to access the user list immediately after attaching a listener in the userService.getUsers function will not yield the desired output.

The code snippet provided:

.service('userService', [function() {
    this.getUsers = function() {
        var users;
        var userList;
        var ref = firebase.database().ref('/users/');
        ref.once('value').then(function(snapshot) {
            users = snapshot.val();
            for(var key in users) {
                users[key].id = key;
                // do some other stuff
            }
            console.log(users); // outputs all users
        }).then(function(){
            userList = users; 
            console.log(userList); // outputs all users
        },(function(error){
            alert('error:  ' + error);
        });
        console.log(userList); // outputs 'undefined'
    }
}]);
Copy after login

Demonstrates this asynchronous behavior. The console output would be:

before attaching listener
after attaching listener
got value
Copy after login

To resolve this issue, you have three options:

1. Use the User List in the Callback:

Move all the necessary code that operates on the user list into the callback:

ref.once('value', function(snapshot) {
        users = snapshot.val();
        for(var key in users) {
            users[key].id = key;
        }
        console.log(users); // outputs all users
    })
Copy after login

2. Return a Promise:

Return a promise from userService.getUsers and chain subsequent operations to it:

this.getUsers = function() {
    var ref = firebase.database().ref('/users/');
    return ref.once('value').then(function(snapshot) {
        users = snapshot.val();
        for(var key in users) {
            users[key].id = key;
            // do some other stuff
        }
        return(users);
    }).catch(function(error){
        alert('error:  ' + error);
    });
}
Copy after login

You can then use the promise to continue processing once the data is loaded:

userService.getUsers().then(function(userList) {
    console.log(userList);
})
Copy after login

3. Use Async and Await (Requires ES2017 Support):

Mark the getUsers function as async and use the await keyword to pause execution until the promise is resolved:

this.getUsers = async function() {
    var ref = firebase.database().ref('/users/');
    const snapshot = await ref.once('value');
    const users = snapshot.val();
    for(var key in users) {
        users[key].id = key;
        // do some other stuff
    }
    return users;
}
Copy after login

You can now use the function like:

async function getAndLogUsers() {
    const userList = await userService.getUsers();
    console.log(userList);
}
Copy after login

By understanding asynchronous execution in Firebase, you can effectively access data from your database and avoid potential undefined references.

The above is the detailed content of Why Does My Firebase Reference Become Undefined Outside the `once()` Function?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template