Elegant Solution for Appending a Vector to Itself
Duplicating the contents of a vector and appending them to the original vector is a common operation. However, implementing this efficiently without a loop can be challenging.
Challenge Discussion
The question highlights the limitations of std::vector::insert and std::copy for this specific task. std::vector::insert prohibits using an iterator to refer to the current vector, and std::copy triggers a segmentation fault when used in this context.
Optimal Solution
The optimal solution involves combining std::vector::resize (or std::vector::reserve) with std::copy_n. The following code demonstrates this approach:
auto old_count = xx.size(); xx.resize(2 * old_count); std::copy_n(xx.begin(), old_count, xx.begin() + old_count);
Alternatively, you can use std::vector::reserve and std::back_inserter:
auto old_count = xx.size(); xx.reserve(2 * old_count); std::copy_n(xx.begin(), old_count, std::back_inserter(xx));
Explanation
std::vector::resize reallocates the vector if its new size exceeds its old capacity. std::copy_n copies the specified number of elements from the beginning of the vector to a new location.
When using std::vector::reserve, std::copy_n is necessary because the end() iterator points one element past the end of the vector. This makes it invalid for insertions.
Conclusion
This solution offers a concise and efficient way to append the contents of a vector to itself without resorting to a loop-based implementation. By utilizing the resize and copy_n operations, you can achieve the desired functionality with minimal code overhead.
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