How to Display Trailing Zeros Using std::cout.precision() in C ?

Correct Use of std::cout.precision() to Display Trailing Zeros

In C , std::cout.precision() sets the precision for floating-point numbers. However, it does not automatically display trailing zeros. To resolve this issue, understanding the appropriate usage of std::cout.precision() is crucial.

In the given code:

#include <iostream>
#include <stdlib.h>
int main() {
  int a = 5;
  int b = 10;
  std::cout.precision(4);
  std::cout << (float)a / (float)b << "\n";
  return 0;
}

The precision is set to 4, but the output is 0.5 instead of 0.5000. This is because the division operation results in a double-precision floating-point value, and std::cout default format does not include trailing zeros.

To display trailing zeros, the std::fixed manipulator must be passed to cout. This instructs cout to use a fixed-point notation, which explicitly displays trailing zeros. The corrected code:

#include <iostream>
#include <stdlib.h>
#include <iomanip>
int main() {
  int a = 5;
  int b = 10;
  std::cout << std::fixed;
  std::cout << std::setprecision(4);
  std::cout << (float)a / (float)b << "\n";
  return 0;
}

Now, the output will be 0.5000, as expected. std::setprecision() sets the precision to 4, and std::fixed ensures that trailing zeros are displayed.

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