How to Strip Debugging Information from Go Code with `gc`?

Stripping Debugging Information from Go Code with gc

As mentioned, the Go compiler (gc) includes debugging information by default. This information allows for more detailed error messages and debugging capabilities. However, it also increases the size of the executable file and makes it easier to decompile the code.

To avoid this, you can specify the -ldflags="-s -w" flag when compiling with gc. The -s flag removes the symbol table from the executable, while the -w flag removes the debugging information.

Here's an example of how to use these flags:

go build -gcflags="-s -w" main.go

This will produce an executable file without any debugging information. However, it's important to note that removing the debugging information can make it more difficult to debug the code if an issue arises.

In Go 1.13 and later, you can also use the -trimpath flag to reduce the length of file paths stored in the executable file. This can be useful for reducing the size of the executable and making it more portable.

Here's an example of how to use the -trimpath flag:

go build -gcflags="-s -w -trimpath=." main.go

By using these flags, you can customize the compilation process of your Go code to meet your specific needs, balancing the need for debugging information with the desire for smaller and more secure executables.

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