How to Decode JSON with Non-Standard Time Formats?

Custom Unmarshal for Non-Standard JSON Time Format

To decode JSON with non-standard time formats into custom structs, built-in marshal and unmarshal functions provide flexibility.

Consider the following JSON:

{
    "name": "John",
    "birth_date": "1996-10-07"
}

And a custom struct to hold the data:

type Person struct {
    Name string `json:"name"`
    BirthDate time.Time `json:"birth_date"`
}

Decoding this JSON using the default decoder fails due to the non-standard time format. To handle this, implement custom marshal and unmarshal functions:

type JsonBirthDate time.Time

func (j *JsonBirthDate) UnmarshalJSON(b []byte) error {
    s := strings.Trim(string(b), "\"")
    t, err := time.Parse("2006-01-02", s)
    if err != nil {
        return err
    }
    *j = JsonBirthDate(t)
    return nil
}

func (j JsonBirthDate) MarshalJSON() ([]byte, error) {
    return json.Marshal(time.Time(j))
}

By adding JsonBirthDate to the Person struct and implementing these functions, the following code will decode the JSON correctly:

person := Person{}
decoder := json.NewDecoder(req.Body)
err := decoder.Decode(&person)
if err != nil {
    log.Println(err)
}
// person.BirthDate now contains the parsed time as a time.Time object

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