How to Encode a `map[string]interface{}` with Gob?

gob: Encoding map[string]interface{}

In this article, we'll explore a common issue encountered while using gob to encode map[string]interface{} data types. When attempting to encode such a map, users may encounter the error "gob: type not registered for interface: map[string]interface {}."

To address this, we introduce a simple solution:

gob.Register(map[string]interface{}{})

By registering the map[string]interface{} type with gob, we enable the encoder to recognize and properly handle this data structure during the encoding process.

Here's an updated code sample that demonstrates how to encode and decode a map[string]interface{} type using gob, after registering the type:

package main

import (
    "bytes"
    "encoding/gob"
    "encoding/json"
    "fmt"
    "log"
)

func CloneObject(a, b interface{}) []byte {
    buff := new(bytes.Buffer)
    enc := gob.NewEncoder(buff)
    dec := gob.NewDecoder(buff)
    enc.Encode(a)
    b1 := buff.Bytes()
    dec.Decode(b)
    return b1
}

func main() {
    var a interface{}
    a = map[string]interface{}{"X": 1}
    b2, err := json.Marshal(&a)
    fmt.Println(string(b2), err)

    gob.Register(map[string]interface{}{})

    var b interface{}
    b1 := CloneObject(&a, &b)
    fmt.Println(string(b1))
}

With gob type registration, encoding and decoding of map[string]interface{} values will function smoothly, and the error message "gob: type not registered for interface: map[string]interface {}" will no longer appear.

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