How Can I Efficiently Remove Array Object Properties Using ES6 Destructuring?

Remove Array Object Properties Efficiently

Eliminating specific properties from objects within an array can be cumbersome using traditional loops. To streamline this process, let's explore a more efficient approach based on ES6 destructuring.

Original For Loop Approach

The traditional method involves using a for loop to iterate over each object and manually delete the property in question:

var array = [{"bad": "something", "good":"something"},{"bad":"something", "good":"something"},...];

for (var i = 0, len = array.length; i < len; i++) {
  delete array[i].bad;
}

While functional, this method is verbose and prone to errors.

ES6 Destructuring to the Rescue

ES6 introduces a convenient way to destructure objects and selectively retain only the desired properties. Using the spread operator ("..."), we can extract all the properties except the ones we want to remove:

const newArray = array.map(({dropAttr1, dropAttr2, ...keepAttrs}) => keepAttrs)

In this case, we create a new array called newArray. The map() function iterates over the original array, and for each object, it destructures it into a new object with all properties except for dropAttr1 and dropAttr2. The remaining properties are collected into the keepAttrs object.

By relying on destructuring instead of loops, you simplify the code, improve readability, and ensure consistency in property removal.

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