Escaping Variables in Printf with "%"
In your code, you attempt to escape the first occurrence of "%v" using "%v". However, this does not work as "%" escapes the percent sign, but it doesn't affect the "v" format specifier.
To escape the "%v" literal, you need to use the "%%" escape sequence. The "%%" sequence represents a literal percent sign. It consumes no value from the provided arguments and simply prints a percent sign.
Therefore, to escape the first occurrence of "%v" in your code, you would use the following:
fmt.Printf("Escape this -> %%v... Do not escape this -> %v", "Unescaped")
This will output:
Escape this -> %v... Do not escape this -> Unescaped
As you can see, the first "%v" is escaped and printed as a literal percent sign, while the second "%v" is used to format the "Unescaped" string.
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