Creating Strings in Java: The Case of "String s = new String("silly")"
When creating strings in Java, it's crucial to understand the behavior of the String class. Unlike many other classes in Java, String literals automatically create String objects without the need for the new keyword. However, creating a new String object using the new operator is explicitly discouraged, as it can lead to unnecessary memory consumption.
To illustrate this, consider the following code:
String s = "No longer silly";
In this case, the literal "No longer silly" is directly assigned to the s variable, resulting in a single String object being created. However, the following code snippet:
String s = new String("silly");
creates an unnecessary additional String object. To avoid this, the recommendation is to use literal assignment whenever possible, as seen in the first example.
However, there may be situations where it's necessary to create String objects dynamically. For instance, consider the following class:
public final class CaseInsensitiveString { private String s; public CaseInsensitiveString(String s) { if (s == null) { throw new NullPointerException(); } this.s = s; } }
In this scenario:
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