Home Backend Development Golang How to Convert a String Time to a Go Time Structure?

How to Convert a String Time to a Go Time Structure?

Nov 16, 2024 am 05:39 AM

How to Convert a String Time to a Go Time Structure?

Converting String Time to Go Time Structure

In Go, you may encounter situations where you need to convert a string time value into a time.Time structure. A common issue arises when dealing with string time values in a specific format that isn't recognized by the default time.Parse() function.

Consider a string time in the format "20171023T183552". To parse this string, we can define our own layout string based on its specific format.

Creating the Layout String

The layout string guides the conversion process by defining how the string time value should be interpreted. For the given example, the format can be described as "YYYYMMDDTHHmmSS". This means:

  • YYYY: Four-digit year
  • MM: Two-digit month
  • DD: Two-digit day
  • T: Separator of date and time
  • HH: Two-digit hour
  • mm: Two-digit minute
  • SS: Two-digit second

Parsing the String

Once the layout string is defined, we can use it with the time.Parse() function to convert the string time value into a time.Time structure.

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s := "20171023T183552"

layout := "20060102T150405"

t, err := time.Parse(layout, s)

if err != nil {

    fmt.Println(err)

}

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Output:

1

2017-10-23 18:35:52 +0000 UTC

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Conclusion

By customizing the layout string, we can successfully parse string time values into time.Time structures in Go, even if their format differs from the standard options provided by the time package.

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