Home > Database > Mysql Tutorial > body text

Why Does MySQL Throw an 'Unknown Column' Error When Using CONCAT in SELECT Queries?

Mary-Kate Olsen
Release: 2024-11-17 17:49:02
Original
362 people have browsed it

Why Does MySQL Throw an

Understanding CONCAT Conditions in MySQL SELECT Queries

When dealing with fields representing names or other concatenated information, MySQL's CONCAT function provides a versatile tool for combining values and performing comparisons. However, using CONCAT in SELECT queries can lead to the error "unknown column" for the alias assigned to the concatenated expression.

To overcome this error, it's important to understand that aliases in SELECT queries are only applicable to the output columns and are not recognized within the query itself. Therefore, to use a CONCAT expression in a WHERE condition, you have two options:

  1. Repeat the CONCAT Expression:

    Instead of using the alias, repeat the CONCAT expression within the WHERE clause:

    SELECT neededfield, CONCAT(firstname, ' ', lastname) as firstlast 
    FROM users
    WHERE CONCAT(firstname, ' ', lastname) = "Bob Michael Jones"
    Copy after login
  2. Wrap the Query:

    Alternatively, you can wrap the original query into a subquery and assign an alias to the CONCAT expression in the subquery:

    SELECT * FROM (
      SELECT neededfield, CONCAT(firstname, ' ', lastname) as firstlast 
      FROM users) base 
    WHERE firstLast = "Bob Michael Jones"
    Copy after login

In both cases, the query successfully compares the concatenated value of the firstname and lastname fields with the provided string, "Bob Michael Jones," and retrieves the desired results.

The above is the detailed content of Why Does MySQL Throw an 'Unknown Column' Error When Using CONCAT in SELECT Queries?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template