How Can I Successfully Execute PHP Code within My CSS Stylesheets to Dynamically Display Images?

How to Execute PHP Commands within CSS Stylesheets

Question:

I need to implement PHP code within my CSS stylesheet to display a DB-generated background image:

<link href="css/<?php echo $theme; ?>/styles.css" rel="stylesheet" type="text/css" />

body{ background-image:url(../../images/<?php echo $theme.'/'.$background; ?>);}

I attempted adding the following header, but it merely outputted the code in HTML format:

<?php header ("Content-type: text/css"); ?>

Answer:

To successfully run PHP code inside CSS, follow these steps:

1. Change the file extension to .php:
   Switch the extension of the CSS file to .php so the server can execute PHP commands.

   Change:

   <link href="css/<?php echo $theme; ?>/styles.css" rel="stylesheet" type="text/css" />

   To:

   <link href="css/<?php echo $theme; ?>/styles.php" rel="stylesheet" type="text/css" />

2. Include the correct header:
   At the beginning of your .php file, include the following header:

   <?php header ("Content-type: text/css"); ?>

3. Shorten PHP tags:
   For convenience, use the shortened PHP echo syntax:

   Change:

   <?php echo $var; ?>

   To:

   <?=$var; ?>

By following these steps, you will be able to run PHP code dynamically within your CSS stylesheets.

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