Why Does `%x` Formatting Output Different Hexadecimal Representations for -1 in Go and C?

Barbara Streisand
Release: 2024-11-19 12:07:03
Original
626 people have browsed it

Why Does `%x` Formatting Output Different Hexadecimal Representations for -1 in Go and C?

Understanding Hexadecimal Representation of 64-bit Integer -1 in Go and C

In Go and C, the %x format is employed to print integers in hexadecimal notation. However, a divergence arises when applied to the negative 64-bit integer -1.

In Go, %x preserves the negative value, displaying "-1", while C outputs "ffffffffffffffff". This disparity stems from Go's strict type handling.

To print the hexadecimal representation of -1 as an unsigned integer in Go, explicit conversion is necessary. Converting it to uint ensures that the value is interpreted as an unsigned type:

fmt.Printf("%d %x %d %x", i, i, uint(i), uint(i))
Copy after login

This results in the output:

-1 -1 4294967295 ffffffff
Copy after login

The second hexadecimal value ("ffffffffff") represents the 2's complement of -1 when treated as an unsigned integer.

The rationale behind this behavior, as explained by Rob Pike, is to preserve the ability to print negative numbers in a compact format. If the %x format always treated arguments as unsigned, there would be no straightforward way to display negative values.

The above is the detailed content of Why Does `%x` Formatting Output Different Hexadecimal Representations for -1 in Go and C?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template