How did Python catch up to Ruby in String Interpolation?

Python's Approach to String Interpolation

While Ruby offers a convenient way to perform string interpolation, Python initially lacked a similar mechanism. In Python 3.6, however, literal string interpolation has been introduced, aligning it with Ruby's approach.

For example:

name = "Spongebob Squarepants"
print(f"Who lives in a Pineapple under the sea? {name}.")

Options Pre-Python 3.6

Before Python 3.6, Python offered alternatives for string interpolation:

• % Operator: Using a dictionary that maps field names to values, similar to Ruby's hash.

name = "Spongebob Squarepants"
print("Who lives in a Pineapple under the sea? %(name)s." % locals())

• .format() Method: Substituting values into placeholders.

name = "Spongebob Squarepants"
print("Who lives in a Pineapple under the sea? {name!s}.".format(**locals()))

• string.Template Class: Employing templates and placeholders for substitution.

tmpl = string.Template("Who lives in a Pineapple under the sea? $name.")
print(tmpl.substitute(name="Spongebob Squarepants"))

In conclusion, Python 3.6 provides a concise and Ruby-like method for string interpolation, while earlier Python versions offer various alternative approaches to achieve similar results.

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