Home > Database > Mysql Tutorial > body text

Why Does 'Warning: mysqli_query() expects parameter 1 to be mysqli, resource given' Error Occur and How to Fix It?

Susan Sarandon
Release: 2024-11-20 12:45:15
Original
926 people have browsed it

Why Does

mysqli_query() Expects Parameter 1 to be mysqli, Resource Given

When attempting to execute a MySQL query using the mysqli_query() function, the "Warning: mysqli_query() expects parameter 1 to be mysqli, resource given" error can occur. This error indicates a mismatch between the type of the first parameter and the expected resource type.

Root Cause:

The root cause of this error is typically related to mixing the mysqli and mysql extensions within your code. These two extensions are not interchangeable and cannot be used together.

Solution:

To resolve this issue, ensure that you are using the same extension throughout your code. If you are using the mysqli extension, all database-related functions must use the mysqli prefix, such as mysqli_connect(), mysqli_select_db(), and mysqli_query().

In the example provided, the code contains mixings of mysql and mysqli functions. To fix it, replace the following lines:

$myConnection= mysql_connect("$db_host","$db_username","$db_pass") or die ("could not connect to mysql");
mysql_select_db("mrmagicadam") or die ("no database");
Copy after login

with:

$myConnection= mysqli_connect("$db_host","$db_username","$db_pass") or die ("could not connect to mysql");
mysqli_select_db($myConnection, "mrmagicadam") or die ("no database");
Copy after login

By making this change, you are ensuring that all database-related functions are using the correct extension, which will eliminate the error and allow the MySQL query to execute successfully.

The above is the detailed content of Why Does 'Warning: mysqli_query() expects parameter 1 to be mysqli, resource given' Error Occur and How to Fix It?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template